5 条题解
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1xhy*114514 (xinghangyuan) LV 9 @ 2022-3-20 20:51:58
#include <stdio.h> #include <string.h> #include <math.h> #include <iostream> using namespace std; int a [1000]; int main() { int n ; cin >> n; int maxx = 0; for(int i = 0,x ;i < n ;i++) { cin >> x; a[x]++; maxx = max(maxx , a[x]); } for(int i = 1 ; i <= 100 ; i++) { if(a[i] == maxx) { cout << i << " " << a[i] << endl; } } }
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02024-9-22 17:04:32@
#include<bits/stdc++.h> using namespace std; int a [1000]; int main(){ int n ; cin >> n; int maxx = 0; for(int i = 0,x ;i < n ;i++) { cin >> x; a[x]++; maxx = max(maxx , a[x]); } for(int i = 1 ; i <= 100 ; i++) { if(a[i] == maxx) { cout << i << " " << a[i] << endl; } } return 0; }
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02024-4-27 15:40:26@
#include<bits/stdc++.h> using namespace std; const int N = 1e6+ 10; const int INF = 0x3f3f3f3f; int n,a[N],x,maxx=-1; int main(){ cin>>n; for(int i=1;i<=n;i++){ cin>>x; a[x]++; if(a[x]>maxx) maxx=a[x]; } for(int i=1;i<=100;i++){ if(a[i]==maxx) cout<<i<<" "<<a[i]<<endl; } }
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02024-3-19 17:38:30@
#include <iostream> using namespace std; int a [1145]; int main() { int n ; cin >> n; int maxx = 0; for(int i = 0,x ;i < n ;i++) { cin >> x; a[x]++; maxx = max(maxx , a[x]); } for(int i = 1 ; i <= 100 ; i++) { if(a[i] == maxx) { cout << i << " " << a[i] << endl; } } }
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02023-2-2 12:04:38@
提示真良心
按着提示做就行了
方法二更容易
方法一:
#include <iostream> #include <stack> #include <cmath> #include <vector> #include <string.h> #include <queue> #include <stdio.h> #include <iomanip> #include <cstdio> #include <algorithm> #define int long long using namespace std; const int N = 1e4+ 10; const int INF = 0x3f3f3f3f; int a[N], maxx[N]/*出现次数*/; signed main() { int n; cin >> n; for(int i = 1; i <= n; i++) { cin >> a[i]; } sort(a + 1, a + n + 1); int k = a[1], cnt = 1, maxn = -INF; for(int i = 2; i <= n + 1; i++) { if(k == a[i])//当前的与上一个相等 { cnt++; } else { maxx[a[i - 1]] = cnt;//上一个数赋值 maxn = max(maxn, cnt);//出现最大次数 k = a[i];//当前值 /* //cnt = 0; if(k == a[i]) { cnt++; } */ cnt = 1;//不要设为0,理由见上注释代码 } } for(int i = 1; i <= 100; i++) { if(maxx[i] == maxn) { cout << i << " " << maxn << endl; } } return 0; }
方法二:
不用注释应该也能看懂
#include <iostream> #include <stack> #include <cmath> #include <vector> #include <string.h> #include <queue> #include <stdio.h> #include <iomanip> #include <cstdio> #include <algorithm> #define int long long using namespace std; const int N = 1e2 + 10; const int INF = 0x3f3f3f3f; int a[N]; signed main() { int n, maxx = -INF; cin >> n; for(int i = 1; i <= n; i++) { int x; cin >> x; a[x]++; maxx = max(maxx, a[x]); } for(int i= 1; i <= 100; i++) { if(a[i] == maxx) { cout << i << " " << maxx << endl; } } return 0; }
- 1
信息
- ID
- 998
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 4
- 标签
- 递交数
- 328
- 已通过
- 163
- 上传者