20 条题解
-
-2
#include <bits/stdc++.h> using namespace std; int main(void) { int n; cin >> n; int x[n]; for (int i = 1; i <= n; i++) { cin >> x[i]; } int y; cin >> y; int m = 1; for (int i = 1; i <= n; i++) { if (x[i] != y) { m++; } if (x[i] == y) { cout << m; break; } } if (m == n + 1) { cout << -1; } return 0; }
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-4
#include <iostream> #include <stack> #include <cmath> #include <vector> #include <string.h> #include <queue> #include <stdio.h> #include <iomanip> #include <cstdio> #include <algorithm> #define int long long using namespace std; const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; int a[N]; signed main() { int n, x; cin >> n; for(int i = 1; i <= n; i++) { cin >> a[i]; } cin >> x; for(int i = 1; i <= n; i++) { if(a[i] == x) { cout << i << endl; return 0; } } cout << "-1" << endl; return 0; }
一个-1都没有
所以用这个也能过
#include <iostream> #include <stack> #include <cmath> #include <vector> #include <string.h> #include <queue> #include <stdio.h> #include <iomanip> #include <cstdio> #include <algorithm> #define int long long using namespace std; const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; int a[N]; signed main() { int n, x; cin >> n; for(int i = 1; i <= n; i++) { cin >> a[i]; } cin >> x; for(int i = 1; i <= n; i++) { if(a[i] == x) { cout << i << endl; break; } } return 0; }
- 1
信息
- ID
- 995
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 6
- 标签
- 递交数
- 1244
- 已通过
- 420
- 上传者