主函数才两行

#include<bits/stdc++.h>
using namespace std;
const int N=1e5+5,INF=0x3f3f3f3f;
typedef long long LL;
int n,m; 
int main()
{
	while(cin>>n>>m)cout<<__gcd(n,m)<<" "<<n/__gcd(n,m)*m<<endl;
	return 0;
}

/*****************************************
备注：
******************************************/
#include <math.h>
#include <stdio.h>
#include <iostream>
#include <string.h>
using namespace std;
int main()
{
	int a,b;
	while(cin >> a >> b)
	{
		int sum = a* b;
		while(b != 0)  // 辗转相除法
		{
			int r = a%b;
			a = b;
			b = r;
		}
		cout << a << " " << sum/a << endl;;
	}


}

#include<bits/stdc++.h>
using namespace std; 
int main(){
	int a,b,c,d;
	while(cin>>a>>b){
		c=a%b;
		d=a*b;
		while(c!=0){
			a=b;
			b=c;
			c=a%b;
		}
		cout<<b<<" "<<d/b<<endl;
	}
}

#include #include #include #include #include #include #include #include using namespace std; const int INF = 0x3f3f3f3f; int main() { int a , b; while(cin >> a >> b) { int sum = a * b; while(b != 0) { int r = a % b; a = b; b = r; } cout << a << " " << sum / a << endl; } return 0; }

#include<algorithm>
using namespace std;
int main(){
	int m,n;
	while(cin >>m>>n){
		int sum = m*n;
		while (n!=0){
			int y=m%n;
			m=n;
			n=y; 
		}
		cout << m << " " << sum/m << endl;
		
	}
	
	return 0;
}