#include <queue>
#include <math.h>
#include <stack>
#include <stdio.h>
#include <iostream>
#include <vector>
#include <iomanip>
#include <string.h>
#include <algorithm>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int main()
{	
	int n;
	cin >> n;
	int b,s,g;
	b = n/100;
	s = n/10%10;
	g = n%10;
	if(b*b*b + g*g*g + s*s*s ==n)
	{
		cout <<"YES";
	}
	else
	{
		cout <<"NO";
	}
	return 0;
}	

#include <iostream>
using namespace std;
int main(){
        int n,num;
        cin>>n;
        num=n;
        int sum=0;
        for(int j=0;j<3;j++){
            sum+=(n%10)*(n%10)*(n%10);
            n/=10;
        }
        if(sum==num)
            cout<<"YES"<<endl;
        else   
            cout<<"NO"<<endl;
    return 0;
}
//钟鼎皓

#include #include using namespace std; const int N=1e3+10; const int INF=0x3f3f3f3f; int a,g,s,b; int main(){ cin>>a; g=a%10; b=a/100; s=a/10%10; if(sss+bbb+ggg==a) cout<<"YES"; else cout<<"NO"; }

#include<bits/stdc++.h> using namespace std; int f(int n) { int bai,shi,ge; for(int i=100; i<=n; i++) { bai=i/100; shi=(i/10)%10; ge=i%10; if(baibaibai+shishishi+gegege==i) { return true; } } return false; } int main() { int n; cin>>n; if(f(n)) cout<<"YES"; else cout<<"NO"; return 0; }

本题思路：分别将每个数提取出，并进行判断。
计算乘方的快捷方式：

pow(double x, double y);

返回值：x的y次方
注意：此函数需要包括库：

#include <cmath>

附上代码（很早以前写的很烂见谅）

//Write by: FSC711300
#include <bits/stdc++.h>
using namespace std;
int main(){
    int n;
    cin>>n;
    int hund=(n-n%100)/100;
    int ten=(n-n%10)/10-hund*10;
    int one=n-hund*100-ten*10;
    if(pow(hund,3)+pow(ten,3)+pow(one,3)==n) cout<<"YES";
    else cout<<"NO";
}

#include <iostream>
using namespace std;
int main(){
        int n,num;
        cin>>n;
        num=n;
        int sum=0;
        for(int j=0;j<3;j++){
            sum+=(n%10)*(n%10)*(n%10);
            n/=10;
        }
        if(sum==num)
            cout<<"YES"<<endl;
        else   
            cout<<"NO"<<endl;
    return 0;
}

#include <iostream>
using namespace std;
int main(){
        int n,num;
        cin>>n;
        num=n;
        int sum=0;
        for(int j=0;j<3;j++){
            sum+=(n%10)*(n%10)*(n%10);
            n/=10;
        }
        if(sum==num)
            cout<<"YES"<<endl;
        else   
            cout<<"NO"<<endl;
    return 0;
}

#include

using namespace std;

int main(){

int x,y;

cin>>x>>y;

if(x+y>10){

	cout<<x*y;

}else{

	cout<<x-y;

}

Copy

}

#include<stdio.h> #include using namespace std; int main() { int a; cin>>a; int b=a%10; int c=a/10%10; int d=a/100; if(bbb+ccc+ddd==a) { cout<<"YES"<<endl; }else { cout<<"NO"<<endl; } }

#include #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include using namespace std; #define LL long long const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; int main() { int n; cin >> n; int b,s,g; b = n/100; s = n/10%10; g = n%10; if(bbb + ggg + sss ==n) { cout <<"YES"; } else { cout <<"NO"; } return 0; }

#include <stdio.h>
#include <iostream>
using namespace std;
int main()
{
	int n;
	cin >> n;
	int b,s,g;
	b = n/100;
	s = n/10%10;
	g = n%10;
	if(b*b*b + g*g*g+s*s*s ==n)
	{
		cout<<"YES";


	}
	else
	{
		cout << "NO";

	}

	








}