13 条题解

  • 3
    @ 2022-11-28 9:56:53
    #include <queue>
    #include <math.h>
    #include <stack>
    #include <stdio.h>
    #include <iostream>
    #include <vector>
    #include <iomanip>
    #include <string.h>
    #include <algorithm>
    using namespace std;
    #define LL long long
    const int N = 1e6 + 10;
    const int INF = 0x3f3f3f3f;
    int a[110][110], n, m;
    int main()
    {
        cin >> n >> m;
    	for(int i = 1; i <= n; i++)
        {
            for(int j = 1; j <= m; j++)
            {
                cin >> a[i][j];
            }
        }
        //其实不用真的转90°
        for(int i = 1; i <= m; i++)//仔细想想这三句
        {
            for(int j = n; j >= 1; j--)//为什么一个加一个减
            {
                cout << a[j][i] << " ";//为什么要反着输出
            }
            puts("");
        }
    	return 0;
    }
    
    • 1
      @ 2025-12-13 10:36:15
      #include<iostream>
      #include<bits/stdc++.h>
      
      using namespace std;
      const int N=1e3+10;
      int a[N][N];
      int main()
      {
      	int n,m;
      	cin >> n >> m;
      	for(int i=1;i<=n;i++)
      	{
      		for(int j=1;j<=m;j++)
      		{
      			cin >> a[i][j];
      		}
      	}
      	for(int i=1;i<=m;i++)
      	{
      		for(int j=n;j>=1;j--)
      		{
      			cout << a[j][i] << " ";
      		}
      		cout << endl;
      	}
      	return 0;
      }
      
      
      • 1
        @ 2025-3-26 13:21:30
        #include <stdio.h>
        int n, m, a[1001][1001], i, j; 
        int main()
        {
        	scanf("%d %d\n", &n, &m);
        	for(i = 1; i <= n; i ++)
        		for(j = 1; j <= m; j ++)
        			scanf("%d", &a[i][j]);
        	for(j = 1; j <= m; j ++)
        	{
        		for(i = n; i; i --) 
        			printf("%d ", a[i][j]);
        		putchar('\n');
        	}
        	return 0;
        }
        

        请反思: 你打开题解时是真的不会做还是懒

        • 0
          @ 2025-3-21 18:08:54
          #include<iomanip> 
          #include<cmath> 
          #include<cstring> 
          #include<cstdio> 
          #include<algorithm> 
          using namespace std;
          const int N=1e2+8;
          const int INF=0x3f3f3f3f;
          int a[N][N],b[N][N],m,n;
          int main()
          {
          	cin>>n>>m;
          	for(int i=1;i<=n;i++)
          		for(int j=1;j<=m;j++)
          			cin>>a[i][j];
          	for(int i=1;i<=n;i++)
          	{
          		for(int j=n;j>=1;j--)
          		{
          			b[i][n-j+1]=a[j][i];
          		}
          	}
          	for(int i=1;i<=m;i++)
          	{
          		for(int j=1;j<=n;j++)
          		{
          			cout<<b[i][j]<<" ";
          		}
          		cout<<endl;
          	}
          	return 0;
          }
          
          
          • 0
            @ 2025-1-24 13:08:34
            #include <bits/stdc++,h>
            using namespace std;
            const int N=1e3+10;
            const int INF=0x3f3f3f3f;
            int n,m,a[N][N];
            int main()
            {
            	cin >> n >> m;
            	for(int i=1;i<=n;i++)
            	{
            		for(int j=1;j<=m;j++)
            		{
            			cin >> a[i][j];
            		}
            	}
            	for(int j=1;j<=m;j++)
            	{
            		for(int i=n;i>=1;i--)
            	    {
            		    cout << a[i][j] << " ";
            		}
            		cout << endl;
            	}
                   return 0;
            }
            //ts2024stu008~~~~~
            

            有标志认证,属三无产品,请大家放心食用

            • 0
              @ 2024-10-25 19:51:58
              #include <iostream>
              #include <bits/stdc++.h>
              using namespace std;
              const int N=1e4+10;
              const int INF=0x3f3f3f3f;
              int n,m,a[N][N];
              int main()
              {
              	cin>>n>>m;
              	for(int i=1;i<=n;i++)
              	{
              		for(int j=1;j<=m;j++)
              		{
              			cin>>a[i][j];
              		}
              	}
              	for(int j=1;j<=m;j++)
              	{
              		for(int i=n;i>=1;i--)
              	    {
              		    cout<<a[i][j]<<" ";
              		}
              		cout<<endl;
              	}
              }
              
              • -1
                @ 2024-10-25 18:20:00

                6

                #include <bits/stdc++.h>
                using namespace std;
                int a[105][105];
                int n,m;
                int main(){
                	cin>>n>>m;
                	for(int i=1;i<=n;i++){
                		for(int j=1;j<=m;j++){
                			cin>>a[i][j];
                		}
                	}
                	for(int j=1;j<=m;j++){
                		for(int i=n;i>=1;i--){
                			cout<<a[i][j]<<" ";
                		}
                		cout<<endl;
                	}
                	return 0;
                }
                
                • -1
                  @ 2023-9-17 18:52:35

                  看似难实则简单

                  #include <iostream>
                  #include <bits/stdc++.h>
                  using namespace std;
                  const int N=1e4+10;
                  const int INF=0x3f3f3f3f;
                  int n,m,a[N][N];
                  int main()
                  {
                  	cin>>n>>m;
                  	for(int i=1;i<=n;i++)
                  	{
                  		for(int j=1;j<=m;j++)
                  		{
                  			cin>>a[i][j];
                  		}
                  	}
                  	for(int j=1;j<=m;j++)
                  	{
                  		for(int i=n;i>=1;i--)
                  	    {
                  		    cout<<a[i][j]<<" ";
                  		}
                  		cout<<endl;
                  	}
                  }
                  
                  • -1
                    @ 2023-9-5 21:36:20
                    //@#@#@#@#@#@#@#
                    #include<iostream>
                    #include<cstdio>
                    #include<string>
                    #include<bits/stdc++.h>
                    #define LL long long
                    using namespace std;
                    const int INF=0x3f3f3f3f;
                    const int N=2e5+10;
                    int a[20000][20000],b,c;
                    int main(){
                    	cin>>b>>c;
                    	for(int i=1;i<=b;i++){
                    		for(int j=1;j<=c;j++){
                    			cin>>a[i][j];
                    		}
                    	}
                    	for(int i=1;i<=c;i++){
                    		for(int j=b;j>=1;j--){
                    			cout<<a[j][i]<<" ";
                    		}
                    		cout<<endl;
                    	}
                    }
                    
                    • -1
                      @ 2023-5-10 20:28:58

                      #include using namespace std; const int N=1e2+10; int a[N][N],n,m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } } for(int i = 1; i <= m; i++) { for(int j = n; j >= 1; j--) { cout << a[j][i] <<" "; } cout<<endl; } return 0; }

                      • -1
                        @ 2023-5-10 20:28:23

                        #include<bits/stdc++.h> using namespace std; const int N=1e2+10; const int INF=0x3f3f3f3f; int n,m,a[N][N]; int main(){ cin>>n>>m; for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) cin>>a[i][j];

                        for(int i=1;i<=m;i++){
                        	for(int j=n;j>=1;j--){
                        		cout<<a[j][i]<<" ";
                        	}
                        	cout<<endl;
                        }
                        
                        return 0;
                        

                        }

                        • -2
                          @ 2023-5-13 14:43:11
                          
                          

                          #include #include <math.h> #include #include <stdio.h> #include #include #include #include <string.h> #include using namespace std; const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; int a[110][110], n, m; int main() { cin >> n >> m; for(int i = 1; i <= n; i++) { for(int j = 1; j <= m; j++) { cin >> a[i][j]; } }

                          for(int i = 1; i <= m; i++)
                          {
                              for(int j = n; j >= 1; j--)
                              {
                                  cout << a[j][i] << " ";
                              }
                              cout << endl;
                          }
                          return 0;
                          

                          }

                          
                          
                          • -3
                            @ 2023-4-12 18:59:26
                            #include <iostream>
                            using namespace std;
                            #define LL long long
                            const int N = 1e6 + 10;
                            const int INF = 0x3f3f3f3f;
                            int a[110][110], n, m;
                            int main()
                            {
                                cin >> n >> m;
                            	for(int i = 1; i <= n; i++)
                                {
                                    for(int j = 1; j <= m; j++)
                                    {
                                        cin >> a[i][j];
                                    }
                                }
                                //其实不用真的转90°
                                for(int i = 1; i <= m; i++)//仔细想想这三句
                                {
                                    for(int j = n; j >= 1; j--)//为什么一个加一个减
                                    {
                                        cout << a[j][i] << " ";//为什么要反着输出
                                    }
                                    puts("");
                                }
                            	return 0;
                            }
                            
                            • 1

                            信息

                            ID
                            1071
                            时间
                            1000ms
                            内存
                            128MiB
                            难度
                            6
                            标签
                            递交数
                            918
                            已通过
                            287
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