7 条题解

  • 1
    @ 2022-8-26 18:05:40
    /*****************************************
    备注:
    ******************************************/
    #include <queue>
    #include <math.h>
    #include <stack>
    #include <stdio.h>
    #include <iostream>
    #include <vector>
    #include <iomanip>
    #include <string.h>
    #include <algorithm>
    using namespace std;
    #define LL long long
    const int N = 1e5 + 10;
    const int INF = 0x3f3f3f3f;
    int main()
    {
    	double n;
    	double a[N];
    	cin >> n;
    	double sum = 0;
    	for(int i = 0 ; i < n ; i++ )
    	{
    		cin >> a[i];
    		sum += a[i];
    	}
    	double s = sum / n;
    	int cnt = 0;
    	for(int i = 0 ; i < n ; i++)
    	{
    		if(a[i] < s)
    			cnt ++;
    	}
    	cout << cnt << endl;
    	return 0;
    }
    
    • 0
      @ 2025-1-24 9:59:46
      #include<bits/stdc++.h>
      using namespace std;
      const int N=1e5+10;
      int main(){
      	int m,l,n,a[N];
      	cin>>n;
      	for(int i=1;i<=n;i++)
      		cin>>a[i];
      	int d=0;
      	for(int i=1;i<=n;i++)
      		d=d+a[i];
      	
      		
      	m=d/n;
      	for(int i=1;i<=n;i++){
      		if(a[i]<=m)
      			l++;
      	} 
      	cout<<l;
      }
      
      • 0
        @ 2024-2-17 18:56:51

        #include #include #include #include #include<bits/stdc++.h>//memset(a,0x3f,sizeof(a)); using namespace std;//cout<<fixed<<setprecision() int a[10005]; int main() { int s,t=0; double y=0; cin>>s; for(int i=0;i<=s-1;i++) { cin>>a[i]; } for(int i=0;i<=s-1;i++) { y+=a[i]; } y/=s; for(int i=0;i<=s-1;i++) { if(y>a[i]) { t++; } } cout<<t; return 0; }

        • 0
          @ 2023-9-10 12:35:35
          #include <bits/stdc++.h>
          using namespace std;
          const int N=1e4+10;
          const int INF=0x3f3f3f3f;
          int a[N];
          double sum;
          int ans,n;
          int main()
          {
          	cin>>n;
          	for(int i=1;i<=n;i++)
          	{
          		cin>>a[i];
          		sum+=a[i];
          	}
          	sum/=n;
          	for(int i=1;i<=n;i++)
          	{
          		if(a[i]<sum)
          		{
          			ans++;
          		}
          	}
          	cout<<ans;
          	return 0;
          }
          
          
          • 0
            @ 2023-4-3 13:53:13
            #include<iostream>
            //#include<iomanip>
            //#include<math.h>
            using namespace std;
            const int N = 1e5 + 10;//1*10^5 + 10
            const int INF = 0x3f3f3f3f;
            double n , a[N] , sum , avg , ans;
            
            int main(){
                cin >> n ;
                
                for(int i = 1;i <= n;i++){
                    cin >> a[i];
                    sum += a[i];
                    }
                    
            	avg = sum / n; 
            	
            	for(int i = 1;i <= n;i++){
                    if(a[i] < avg){
                    	ans ++;
            		}
                    }  
                    
                //if(i == 1){
                //    pass
                //}else{
                //    pass
                //}
            
                cout << ans ;
                return 0;
            }
            
            • 0
              @ 2023-4-2 21:45:16
              using namespace std;
              const int N = 1e5 + 10;
              const int INF = 0x3f3f3f3f;
              int main(){
              	double n;
              	double a[N];
              	cin >> n;
              	double sum = 0;
              	for(int i = 0 ; i < n ; i++ ){
              		cin >> a[i];
              		sum += a[i];
              	}
              	double s = sum / n;
              	int cnt = 0;
              	for(int i = 0 ; i < n ; i++){
              		if(a[i] < s)
              			cnt ++;
              	}
              	cout << cnt << endl;
              	return 0;
              }
              
              • -1
                @ 2023-1-30 16:46:56

                #include

                #include

                #include

                #include

                #include

                #include

                #include

                #include

                using namespace std;

                int main()

                {

                double s=0,x;

                int b=0,n;

                cin >> n;

                double a[n+1];

                for(int i=1;i<=n;i++)

                {

                cin >> a[i];

                s += a[i];

                }

                x = s / n;

                for(int i=n;i>=1;i--)

                {

                if(a[i] < x)b++;

                }

                cout << b;

                return 0;

                }

                • 1

                信息

                ID
                1018
                时间
                1000ms
                内存
                256MiB
                难度
                6
                标签
                递交数
                674
                已通过
                221
                上传者