p822和p879的结合，想进阶可做p825

#include<iostream>
#include<iomanip>
#include<stdio.h>
#include<math.h>
#include<string>
#include<cstring>
using namespace std;
int main(){
    double a,b,c,p,maxx,sum;
	cin>>a>>b>>c;
	maxx=max(a,max(b,c));
	sum=a+b+c;
	if(maxx<sum-maxx){
		p=(a+b+c)/2;
	    printf("%.2lf",sqrt(p*(p-a)*(p-b)*(p-c)));
	}else{
		cout<<"No Solution.";
	}
}

#include <stdio.h>
#include <iostream>
#include <math.h>
#include<iomanip>
using namespace std;
int main()
{
	double a,b,c,p,x;
	cin >> a >> b >> c;
	p=(a+b+c)/2;
	x=(p-a)*(p-b)*(p-c)*p;
	double s=sqrt(x);
	if(a+b > c && a + c > b && c + b > a)
	{
		cout<<fixed<<setprecision(2)<<s<<endl;
	}
		else
		{
			cout<<"No Solution.";
		}

}

#include <stdio.h> #include <iostream> #include <math.h> #include<iomanip> using namespace std; int main() { double a,b,c,p,x; cin>>a>>b>>c; p=(a+b+c)/2; x=(p-a)(p-b)(p-c)*p; double s=sqrt(x); if(a+b>c&&a+c>b&&c+b>a) { cout<<fixed<<setprecision(2)<<s<<endl; } else { cout<<"No Solution."; }

}