6 条题解

  • 1
    @ 2023-6-14 19:09:50
    #include <iostream>
    #include <stdio.h>
    #include <iomanip>
    #include <math.h>
    using namespace std;
    const int N = 1e6 + 10;
    const int INF = 0x3f3f3f3f;
    int main()
    {
    	int x1 , y1 , x2 , y2 , jl1 , jl2 , j;
    	cin >> x1 >> y1 >> x2 >> y2;
    	jl1 = fabs( x1 - x2 ); 
    	jl2 = fabs( y1 - y2 );
    	j = jl1 + jl2;
    	cout << j;
    	return 0;
    }
    
    • 1
      @ 2022-10-30 16:50:32
      #include <bits/stdc++.h>
      
      using namespace std;
      
      int main(void)
      {
          int x1, y1;
          int x2, y2;
      
          int i, j;
      
          cin >> x1 >> y1 >> x2 >> y2;
      
          i = abs(x1 - x2);
          j = abs(y1 - y2);
      
          cout << i + j;
      
          return 0;
      }
      
      • 0
        @ 2024-3-29 19:51:49

        **#include<iostream> using namespace std; int main() { int xx,yy,x,y; cin >> x >> y >> xx >> yy; int sum = fabs(xx - x) + fabs(yy - y); cout << sum << endl; return 0; } **

        • 0
          @ 2023-3-12 16:03:53

          #include <iostream> #include <stdio.h> #include <string.h> #include <queue> #include <math.h> #include <vector> #include <algorithm> #include <iomanip> #include <stack> #include <bits/stdc++.h> using namespace std; int main(void){ int x1,y1; int x2,y2;

          cin>> x1>>y1>>x2>>y2;
          int i,j;
          i=abs(x1-x2);
          j=abs(y1-y2);
          cout << i+j;
          return 0;
          

          }

          • -1
            @ 2022-8-13 18:46:18
            #include <iostream>
            #include <cstdio>
            #include <cstring>
            #include <string>
            #include <iomanip>
            // #include <cmath>
            using namespace std;
            #define long long LL
            const int N = 1e6+6;
            const int INF = 0x3f3f3f3f;
            int x1,y1,x2,y2;
            int ans(int x){
                if (x > 0) return x;
                else return 0 - x;
            }
            int manhaton(int a1,int b1,int a2,int b2){
                return ans(a1 - a2) + ans(b1 - b2);
            }
            int main(){
                cin >> x1 >> y1 >> x2 >> y2;
                cout << manhaton(x1,y1,x2,y2);
                return 0;
            }
            
          • -4
            @ 2022-2-8 19:31:18

            #include <stdio.h> #include <iostream> #include <math.h> using namespace std; int main() { int x1 , y1 , x2 , y2; cin>> x1 >> y1 >> x2 >> y2; int a , b , a1 , b1 , d; a = x1 - x2 ; b = y1 - y2 ; a1 = fabs(a); b1 = fabs(b); d = a1 + b1; cout << d ;

            }

            • 1

            信息

            ID
            834
            时间
            1000ms
            内存
            128MiB
            难度
            4
            标签
            (无)
            递交数
            497
            已通过
            222
            上传者