3 条题解

  • 0
    @ 2024-6-15 10:29:58

    先把表打出来:

    #include <bits/stdc++.h>
    using namespace std;
    
    int n,cnt;
    
    void dfs(int step,int x)
    {
    	if(step > n)
    	{
    		cnt++;
    		return;
    	}
    	if(x) dfs(step,x - 1);
    	dfs(step + 1,x + 1);
    	return;
    }
    
    signed main()
    {
    	for(n = 1;n <= 18;n++)
    	{
    		cnt = 0;
    		dfs(1,0);
    		printf("%d,",cnt);
    	}
    	return 0;
    }
    

    得出答案序列:

    0,1,2,5,14,42,132,429,1430,4862,16796,58786,208012,742900,2674440,9694845,35357670,129644790,477638700

    然后输出。

    #include <bits/stdc++.h>
    using namespace std;
    
    int n;
    int ans[19] = {0,1,2,5,14,42,132,429,1430,4862,16796,58786,208012,742900,2674440,9694845,35357670
    ,129644790,477638700};
    
    signed main()
    {
    	scanf("%d",&n);
    	printf("%d",ans[n]);
    	return 0;
    }
    
    • 0
      @ 2023-4-25 21:04:07

      image

      搞笑的吧?

      #include <bits/stdc++.h>
      using namespace std;
       
      long long n, a[20];
       
      int main ()
      {
      	cin >> n;
      	a[0] = 1, a[1] = 1;
      	for (int i = 2; i <= n; ++i)
      		for (int j = 0; j <= i - 1; ++j)
      			a[i] += a[j] * a[i-1-j];
      	cout << a[n];
      }
      
      • -1
        @ 2023-3-26 20:14:41

        要题解

        • 1

        信息

        ID
        665
        时间
        1000ms
        内存
        256MiB
        难度
        1
        标签
        递交数
        39
        已通过
        28
        上传者