最短

#include<bits/stdc++.h>
#define long long int 
using namespace std;
const int N=1e5+5,INF=0x3f3f3f3f;
int a,b,c,d;
int main()
{
	cin>>a>>b>>c>>d;
	cout<<(c*60+d-a*60-b)/60<<" "<<(c*60+d-a*60-b)%60;
	return 0;
}

ACcode

两种情况，判断一下d<b时的情况

#include<bits/stdc++.h>
using namespace std;
int a,b,c,d;
int main(){
	cin>>a>>b>>c>>d;
	if(c>=a&&d>=b) cout<<c-a<<" "<<d-b;
	else cout<<c-a-1<<" "<<d+60-b;
}

#include using namespace std; int main(){ int a,b,c,d; cin>>a>>b>>c>>d; int t=c60+d-a60-b; cout<<t/60<<" "<<t%60; return 0; } #思考