1 条题解
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1莫言 (slz莫言) LV 10 @ 2024-12-18 12:52:45
#include <bits/stdc++.h> #define LL long long using namespace std; const int INF = 0x3f3f3f3f; const int N = 100 + 10; int n , m; int a [N] [N]; int main() { cin >> n; for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { cin >> a [i] [j]; } } cin >> m; for (int i = 1; i <= n; i++) { for (int j = 1; j <= n; j++) { a [i] [j] /= m; cout << a [i] [j] << " "; } cout << "\n"; } return 0; }
- 1
信息
- ID
- 3101
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 2
- 标签
- 递交数
- 13
- 已通过
- 10
- 上传者