1 条题解
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1
#include <iostream> #include <cstdio> #include <cmath> using namespace std; int main() { double a,b,c,x1,x2; cin >> a >> b >> c; if(a == 0 || b*b - 4*a*c < 0) cout << "No answer!"; else { x1 = (-b + sqrt(b * b - 4 * a * c)) / (2 * a); x2 = (-b - sqrt(b * b - 4 * a * c)) / (2 * a); /* if(x1 > x2) swap(x1,x2); */ printf("The first root is: %.2f\nThe second root is: %.2f",x1,x2); } return 0; }
信息
- ID
- 1493
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 7
- 标签
- 递交数
- 103
- 已通过
- 27
- 上传者