1 条题解
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  2
#include <iostream> #include <cstdio> #include <cmath> using namespace std; int main() { double a,b,c,x1,x2; cin >> a >> b >> c; if(a == 0 || b*b - 4*a*c < 0) cout << "No answer!"; else { x1 = (-b + sqrt(b * b - 4 * a * c)) / (2 * a); x2 = (-b - sqrt(b * b - 4 * a * c)) / (2 * a); /* if(x1 > x2) swap(x1,x2); */ printf("The first root is: %.2f\nThe second root is: %.2f",x1,x2); } return 0; } 
- 1
 
信息
- ID
 - 1493
 - 时间
 - 1000ms
 - 内存
 - 256MiB
 - 难度
 - 7
 - 标签
 - 递交数
 - 104
 - 已通过
 - 28
 - 上传者