7 条题解

  • 5
    @ 2023-10-22 18:52:44

    哪个逼那么不要脸抄我代码

    点赞!!!

    #include <bits/stdc++.h> 
    using namespace std; 
    long long a[1010][1010],ans[1010][1010]; 
    int main() 
    { 
    	int n,m,k,t; 
    	cin>>n>>m>>k>>t; 
    	for(int i=1;i<=n;i++) 
    		for(int j=1;j<=m;j++) 
    		{ 
    			scanf("%lld",&a[i][j]); 
    			ans[i][j]=a[i][j]-a[i-1][j]-a[i][j-1]+a[i-1][j-1]; 
    		} 
    	while(k--) 
    	{ 
    		long x1,x2,y1,y2,num; 
    		scanf("%lld%lld%lld%lld%lld",&x1,&y1,&x2,&y2,&num); 
    		ans[x2+1][y2+1]+=num; 
    		ans[x1][y1]+=num; 
    		ans[x1][y2+1]-=num; 
    		ans[x2+1][y1]-=num; 
    	} 
    	for(int i=1;i<=n;i++) 
    	{ 
    		for(int j=1;j<=m;j++) 
    		{ 
    			ans[i][j]+=ans[i][j-1]+ans[i-1][j]-ans[i-1][j-1]; 
    			printf("%lld ",ans[i][j]);
    		} 
    		printf("\n"); 
    	} 
    	for(int i=1;i<=n;i++) 
    		for(int j=1;j<=m;j++) 
    		ans[i][j]+=ans[i][j-1]+ans[i-1][j]-ans[i-1][j-1]; 
    	while(t--) 
    	{ 
    		int x1,x2,y1,y2; 
    		scanf("%lld%lld%lld%lld",&x1 ,&y1,&x2,&y2); 
    		printf("%lld\n",ans[x2][y2]-ans[x1-1][y2]-ans[x2][y1-1]+ans[x1-1][y1-1]); 
    	} 
    	return 0; 
    }
    

    哪个逼那么不要脸抄我代码

    点赞!!!

    • 2
      @ 2023-4-30 21:22:54

      终于,终于(激动),终于做出来辣!!!!!!!!!!!!!!!!!!!!! 真的太复杂啦:

      ll x1,y1,x2,y2,c;
      	while(p--){
      		scanf("%lld %lld %lld %lld %lld",&x1,&y1,&x2,&y2,&c);
      		b[x1][y1]+=c;//利用差分快速加法
      		b[x1][y2+1]-=c;
      		b[x2+1][y1]-=c;
      		b[x2+1][y2+1]+=c;
      	}
      	for(int i=1;i<=n;i++){//构造加法后的a数组
      		for(int j=1;j<=m;j++){
      			b[i][j]+=b[i-1][j]+b[i][j-1]-b[i-1][j-1];
      			printf("%lld ",b[i][j]);
      		}
      		printf("\n");
      	}
      	for(int i=1;i<=n;i++)//再构造a的前缀和数组
      		for(int j=1;j<=m;j++)b[i][j]+=b[i-1][j]+b[i][j-1]-b[i-1][j-1];
      	while(q--){
      		scanf("%lld %lld %lld %lld",&x1,&y1,&x2,&y2);
      		ll sum=b[x2][y2]-b[x1-1][y2]-b[x2][y1-1]+b[x1-1][y1-1];//利用前缀和输出
      		printf("%lld\n",sum);
      	}
      	return 0;
      }
      
      • 1
        @ 2023-10-29 17:40:11
        #include <bits/stdc++.h>
        using namespace std;
        const int N = 1e3 + 10;
        const int INF = 0x3f3f3f3f;
        long long n , m , p , q , x , y , x2 , y2 , z;
        long long cf[N][N] , a[N][N] , s[N][N];
        int main()
        {
        	cin >> n >> m >> p >> q; 
        
        	for( int i = 1 ; i <= n ; i++ )
        	{ 
        		for( int j = 1 ; j <= m ; j++ )
        		{ 
        			cin >> a[i][j]; 
        			cf[i][j] = a[i][j] - a[i-1][j] - a[i][j-1] + a[i-1][j-1]; 
        		} 
        	}
        
        	while( p-- )
        	{
        		cin >> x >> y >> x2 >> y2 >> z;
        		cf[x][y] += z;
        		cf[x][y2+1] -= z;
        		cf[x2+1][y] -= z;
        		cf[x2+1][y2+1] += z;
        	}
        
        	for( int i = 1 ; i <= n ; i++ )
        	{
        		for( int j = 1 ; j <= m ; j++ )
        		{
        			a[i][j] = a[i-1][j] + a[i][j-1] - a[i-1][j-1] + cf[i][j];
        			s[i][j] = s[i-1][j] + s[i][j-1] - s[i-1][j-1] + a[i][j];
        			cout << a[i][j] << " ";
        		}
        		cout << endl;
        	}
        
        	while( q-- )
        	{
        		cin >> x >> y >> x2 >> y2;
        		cout << s[x2][y2] - s[x-1][y2] - s[x2][y-1] + s[x-1][y-1] << endl;
        	}
        	return 0;
        }
        
        • 0
          @ 2024-10-29 17:09:32
          #include <bits/stdc++.h>
          using namespace std;
          const int N = 1e3 + 10;
          const int INF = 0x3f3f3f3f;
          long long n , m , p , q , x , y , x2 , y2 , z;
          long long cf[N][N] , a[N][N] , s[N][N];
          int main()
          {
          	cin >> n >> m >> p >> q; 
          
          	for( int i = 1 ; i <= n ; i++ )
          	{ 
          		for( int j = 1 ; j <= m ; j++ )
          		{ 
          			cin >> a[i][j]; 
          			cf[i][j] = a[i][j] - a[i-1][j] - a[i][j-1] + a[i-1][j-1]; 
          		} 
          	}
          
          	while( p-- )
          	{
          		cin >> x >> y >> x2 >> y2 >> z;
          		cf[x][y] += z;
          		cf[x][y2+1] -= z;
          		cf[x2+1][y] -= z;
          		cf[x2+1][y2+1] += z;
          	}
          
          	for( int i = 1 ; i <= n ; i++ )
          	{
          		for( int j = 1 ; j <= m ; j++ )
          		{
          			a[i][j] = a[i-1][j] + a[i][j-1] - a[i-1][j-1] + cf[i][j];
          			s[i][j] = s[i-1][j] + s[i][j-1] - s[i-1][j-1] + a[i][j];
          			cout << a[i][j] << " ";
          		}
          		cout << endl;
          	}
          
          	while( q-- )
          	{
          		cin >> x >> y >> x2 >> y2;
          		cout << s[x2][y2] - s[x-1][y2] - s[x2][y-1] + s[x-1][y-1] << endl;
          	}
          	return 0;
          }
          小鸟专属
          
          • 0
            @ 2023-10-22 20:30:35

            #include <bits/stdc++.h> using namespace std; const int N=1e3+10;

            long long n,m,p,q,cf[N][N],a[N][N],s[N][N]; long long x,y,x2,y2,z;

            int main(){ cin>>n>>m>>p>>q; for(int i=1;i<=n;i++){ for(int j=1;j<=m;j++){ cin>>a[i][j]; cf[i][j]=a[i][j]-a[i][j-1]+a[i-1][j-1]; } }

            while(p--){
            	cin>>x>>y>>x2>>y2>>z;
            	cf[x][y]+=z;
            	cf[x][y2+1]-=z;
            	cf[x2+1][y]-=z;
            	cf[x2+1][y2+1]+=z;
            }
            
            for(int i=1;i<=n;i++){
            	for(int j=1;j<=m;j++){
            		a[i][j]=a[i-1][j]+a[i][j-1]-a[i-1][j-1]+cf[i][j];
            		s[i][j]=s[i-1][j]+s[i][j-1]-s[i-1][j-1]+a[i][j];
            		cout<<a[i][j]<<" ";
            	}
            	cout<<endl;
            }
            
            while(q--){
            	cin>>x>>y>>x2>>y2;
            	cout<<s[x2][y2]-s[x-1][y2]-s[x2][y-1]+s[x-1][y-1]<<endl;
            }
            return 0;
            

            }

            • 0
              @ 2023-10-11 20:31:04

              #include<iostream> #include<cmath> #include<string> #include<iomanip> using namespace std; const int N = 1e3 + 10; long long n , m , p , q , a[N][N] , s[N][N] , x , y , x2 , y2 , cf[N][N] , tmp; int main(){ cin >> n >> m >> q; for(int i = 1;i <= n;i++) { for(int j = 1; j <= m;j++) { cin >> a[i][j]; cf[i][j] = a[i][j] - a[i-1][j] - a[i][j-1] + a[i-1][j-1]; } }

              while(p--)
              {
              	cin >> x >> y >> x2 >> y2;
              	cout << sum[x2][y2] - sum[x-1][y2] - sum[x2][y-1] + sum[x-1][y-1] << endl;
              	
              }
              
              return 0;
              

              }保存一下代码哈,晚点再发真代码

            • 0
              @ 2023-4-30 16:54:41

              #include<bits/stdc++.h> using namespace std; const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; long long a[1010][1010],ans[1010][1010]; int main() { int n,m,k,t; cin>>n>>m>>k>>t; for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) { scanf("%lld",&a[i][j]); ans[i][j]=a[i][j]-a[i-1][j]-a[i][j-1]+a[i-1][j-1]; } while(k--) { long long x1,x2,y1,y2,num; scanf("%lld%lld%lld%lld%lld",&x1,&y1,&x2,&y2,&num); ans[x2+1][y2+1]+=num; ans[x1][y1]+=num; ans[x1][y2+1]-=num; ans[x2+1][y1]-=num; } for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) { ans[i][j]+=ans[i][j-1]+ans[i-1][j]-ans[i-1][j-1]; printf("%lld ",ans[i][j]); } printf("\n"); } for(int i=1;i<=n;i++) for(int j=1;j<=m;j++) ans[i][j]+=ans[i][j-1]+ans[i-1][j]-ans[i-1][j-1]; while(t--) { int x1,x2,y1,y2; scanf("%lld%lld%lld%lld",&x1 ,&y1,&x2,&y2); printf("%lld\n",ans[x2][y2]-ans[x1-1][y2]-ans[x2][y1-1]+ans[x1-1][y1-1]); } return 0; }

              • 1

              信息

              ID
              1285
              时间
              1000ms
              内存
              256MiB
              难度
              7
              标签
              递交数
              667
              已通过
              134
              上传者