10 条题解

  • 3
    @ 2021-11-6 20:57:28 
    /*****************************************
备注：
******************************************/
#include <queue>
#include <math.h>
#include <stack>
#include <stdio.h>
#include <iostream>
#include <vector>
#include <iomanip>
#include <string.h>
#include <algorithm>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int x[N],y[N],z[N];
int main()
{
	string a,b;
	cin >> a >> b;
	int lena = a.size();
	int lenb = b.size();
	for(int i = 0 ; i < lena ; i++)
		x[i] = a[lena - i - 1] - '0';
	for(int i = 0 ; i < lenb ; i++)
		y[i] = b[lenb - i - 1] - '0';
	for(int i = 0 ; i < lena ; i++)
		for(int j = 0 ;j  < lenb ; j++)
		{
			z[i+j] += x[i] * y[j];
			z[i+j + 1] += z[i+j]/10;
			z[i+j] %= 10;
		}
	int len = lena + lenb  ;
	while( !z[len] && len > 0) len--;

	for(int i = len ; i >= 0 ; i--)
		cout << z[i];
	return 0;
}
    • 1
      @ 2023-11-26 18:13:12 
      #include <iostream>
using namespace std;
#define ll long long
const int N =1e5+10;
const int INF =0x3f3f3f3f;
string a,b;
int a1[N],b1[N],c1[N],lena,lenb,lenc,x;
int main()
{
	cin>>a>>b;
	lena=a.size();
	lenb=b.size();
	for(int i=0;i<lena;i++)
	{
		a1[i]=a[lena-i-1]-'0';
	}
	for(int i=0;i<lenb;i++)
	{
		b1[i]=b[lenb-i-1]-'0';
	}
	for(int i=0;i<lenb;i++)
	{
		x=0;
		for(int j=0;j<lena;j++)
		{
			c1[i+j]+=a1[j]*b1[i]+x;
			x=c1[i+j]/10;
			c1[i+j]%=10;
		}
		c1[lena+i]=x;
	}
	lenc=lena+lenb;
	while(c1[lenc]==0&&lenc>0)
	{
		lenc--;
	}
	for(int i=lenc;i>=0;i--)
	{
		cout<<c1[i];
	}
 	return 0;
}
      • 0
        @ 2024-3-17 15:47:14

        #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; } #include <iostream> using namespace std; #define ll long long const int N =1e5+10; const int INF =0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin>>a>>b; lena=a.size(); lenb=b.size(); for(int i=0;i<lena;i++) { a1[i]=a[lena-i-1]-'0'; } for(int i=0;i<lenb;i++) { b1[i]=b[lenb-i-1]-'0'; } for(int i=0;i<lenb;i++) { x=0; for(int j=0;j<lena;j++) { c1[i+j]+=a1[j]*b1[i]+x; x=c1[i+j]/10; c1[i+j]%=10; } c1[lena+i]=x; } lenc=lena+lenb; while(c1[lenc]==0&&lenc>0) { lenc--; } for(int i=lenc;i>=0;i--) { cout<<c1[i]; } return 0; }

        • 0
          @ 2024-3-17 15:43:31

          不是，看题解的都有啥实力锕

          • 0
            @ 2023-12-5 16:52:28

            这道题其实和高精度加法很像，只要在高精度加法的基础上稍加修改就可以了。

            上代码↓

            #include<bits/stdc++.h>
using namespace std;
int c[100000];
int a1[100000],b1[100000];
int len1,len2,len3,x;
string a,b;
int r,y;
int main(){
	cin>>a>>b;
	len1=a.size();
	len2=b.size();
	for(int i=0;i<len1;i++)a1[i]=a[len1-i-1]-'0';
	for(int i=0;i<len2;i++)b1[i]=b[len2-i-1]-'0';
	for(int i=0;i<len1;i++){
		for(int j=0;j<len2;j++){
			c[i+j]+=a1[i]*b1[j];
			c[i+j+1]+=c[i+j]/10;
			c[i+j]%=10;
		}
	}
	len3=len1+len2;
	while(c[len3]==0&&len3>0){
		len3--;
	}
	for(int i=len3;i>=0;i--)cout<<c[i];
	return 0;
}

            点个赞呗

            • 0
              @ 2023-11-25 20:18:56

              #include <queue> #include <math.h> #include <stack> #include <stdio.h> #include <iostream> #include <vector> #include <iomanip> #include <string.h> #include <algorithm> using namespace std; #define LL long long const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; string a,b; int a1[N],b1[N],c1[N],lena,lenb,lenc,x; int main() { cin >> a; cin >> b; lena = a.size(); lenb = b.size();

              for(int i = 0;i <lena;i++)
{
	a1[i]= a[lena-i-1] -'0';
}
for(int i = 0;i <lenb;i++)
{
	b1[i]= b[lenb-i-1] -'0';
}
for(int i = 0;i < lenb;i++)
{
	x =0;
	for(int j = 0;j < lena;j++)
	{
		c1[i + j]+=a1[j]* b1[i]+x;
		x = c1[i + h]/10;
		c1 [i+j]%=10;
	}
	c1[lena + i]=x;
} 
lenc = lena +lenb;
while(c1[lenc]==0&&lenc>0)
	lenc--;
for(int i = lenc;i >= 0;i--)
	cout <<c1[i];
return 0;

              }

              • 0
                @ 2023-11-25 20:10:58

                #include <iostream> #include <iomanip> #include <cmath> #include <string> #include <cstring> #include <algorithm> #include <cstdio> using namespace std; const int N =1e5+10; string a , b; int lena , lenb , lenc , a1[N] , b1[N] , c1[N] , x; int main() { cin>>a>>b; lena = a.size(); lenb = b.size(); for(int i = 1;i <= lena;i++) { a1[i] = a[lena - i] - '0'; } for(int i = 1;i <= lenb;i++) { b1[i] = b[lenb - i] - '0'; } for(int i = 1;i <= lenb;i++) { x = 0; for(int j = 1;j<= lena;j++) { c1[i + j - 1] += a1[j] * b1[i] + x; x = c1[i + j - 1] / 10; c1[i + j - 1] %= 10; } c1[i + lena] = x; } lenc = lena + lenb; while(c1[lenc] == 0 && lenc > 1) { lenc--; } for(int i = lenc;i >= 1;i--) { cout<<c1[i]; } return 0; }

                • [ ] > ````````````````````````````````````````````````````````````````````````````````````````````````**************

                  **************


                  **********

                  ******

                  **
                • 0
                  @ 2023-10-29 20:27:29 
                  #include <bits/stdc++.h>
using namespace std;
#define LL long long
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
int x[N],y[N],z[N];
int main()
{
	string a,b;
	cin >> a >> b;
	int lena = a.size();
	int lenb = b.size();
	for(int i = 0 ; i < lena ; i++)
		x[i] = a[lena - i - 1] - '0';
	for(int i = 0 ; i < lenb ; i++)
		y[i] = b[lenb - i - 1] - '0';
	for(int i = 0 ; i < lena ; i++)
		for(int j = 0 ;j  < lenb ; j++)
		{
			z[i+j] += x[i] * y[j];
			z[i+j + 1] += z[i+j]/10;
			z[i+j] %= 10;
		}
	int len = lena + lenb  ;
	while( !z[len] && len > 0) len--;

	for(int i = len ; i >= 0 ; i--)
		cout << z[i];
	return 0;
}
                  • 0
                    @ 2023-10-25 19:47:16

                    #include <queue> #include <math.h> #include <stack> #include <stdio.h> #include <iostream> #include <vector> #include <iomanip> #include <string.h> #include <algorithm> using namespace std; const int N=1e5+10; const int INF=0x3f3f3f3f; char a[N],b[N]; int a1[N],b1[N],c1[N],lenc,x; int main(){ cin>>a>>b; int lena=strlen(a); int lenb=strlen(b); for(int i=0;i<lena;i++) a1[i]=a[lena-i-1]-'0'; for(int j=0;j<lenb;j++) b1[j]=b[lenb-j-1]-'0';

                    for(int i=0;i<lenb;i++){
	x=0;
	for(int j=0;j<lena;j++){
		c1[i+j]+=a1[j]*b1[i]+x;
		x=c1[i+j]/10;
		c1[i+j]%=10;
		
	}
	c1[lena+i]=x;
	
}

lenc=lena+lenb;
while(c1[lenc]==0&&lenc>0)
	lenc--;
for(int i=lenc;i>=0;i--)
	cout<<c1[i];



return 0;

                    }

                    • -4
                      @ 2022-3-19 10:11:37 
                      #include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
const int INF = 0x3f3f3f3f;
char aa[N],bb[N],cc[N];
int a[N],b[N],c[N];
int main()
{
	cin >> aa >> bb;
	int lena = strlen(aa);
	int lenb = strlen(bb);
	for(int i = 0;i < lena;i++)
		a[i] = aa[lena - i - 1] - '0';
	for(int i = 0;i < lenb;i++)
		b[i] = bb[lenb - i - 1] - '0';
	for(int i = 0;i < lena;i++)
	{
		for(int j = 0;j < lenb;j++)
		{
			c[i+j] +=a[i] * b[j];
			if(c[i+j] > 9)
			{
				c[i+j+1]+= c[i+j]/10;
				c[i+j] = c[i+j]%10;
			}
		}
	}
	int len = lena +lenb;
	while(c[len] == 0 && len > 0)
	{
		len--;
	}	
	for(int i = len;i >=0;i--)
		cout << c[i];
	return 0;
}
                      • 1

                      高精度乘法

                      信息

                      ID
                      1187
                      时间
                      1000ms
                      内存
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                      难度
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