18 条题解

  • 3
    @ 2025-1-23 11:13:08
    #include<iostream>
    using namespace std;
    int main()
    {
    	int a,b;
    	cin>>a>>b;
    	cout<<a+b;
    }
    
    • 1
      @ 2025-4-19 19:45:44

      #include using namespace std; int main() { int a,b; cin >> a >> b; cout << a+b; return 0; }

      • 1
        @ 2024-7-26 10:58:29

        A+B Problem题解

        新用户强烈建议阅读此帖

        首先我们要理清思路

        1.需要用到什么样的头文件?

        2.用什么样的数据范围?

        3.思路是什么?

        首先题目中的数据范围是1a,b≤10^6, 而int 的范围是-2147483648-2147483647 正合题意,所以数据类型可以用int

        话不多说,直接上代码

        #include<iostream>//导入头文件,iostream里面是标准输入输出流(我说的什么?) 
        using namespace std;//使用标准命名空间 
        int main(){//主函数,程序的入口 
        	int a,b;//创建a,b两个整型变量 
        	cin>>a>>b;//输入 a , b 两个变量 
        	cout<<a+b; //输出a+b的内容 
        	return 0; 
        }
        

        本蒟蒻发的第一篇题解,请多多支持喵~~

        • 0
          @ 2025-4-23 18:57:08

          #include <bits/stdc++.h> using namespace std; int main() { int a,b; while(cin >> a >> b) { int sum = a* b; while(b != 0) { int t = a%b; a = b; b = t; } cout << a << " " << sum/a << endl;; } return 0; }

          • 0
            @ 2025-4-21 20:16:38
            ```cpp
            #include <bits/stdc++.h>
            using namespace std;
            #define LL long long
            const int N = 1e5 + 10;
            const int INF = 0x3f3f3f3f;
            string a1 , b1;
            int a[500] , b[500] , c[500];
            int main()
            {
                cin >> a1 >> b1;
                int lena = a1.size();
                int lenb = b1.size();
                for ( int i = 0 ; i < lena ; i++ )
            	{
                    a[ lena - i ] = a1[i] - '0';
                }
                for ( int i = 0 ; i < lenb ; i++ )
            	{
                    b[ lenb - i ] = b1[i] - '0';
                }
                int lenc = 1 , x = 0;
                while  ( lenc <= lena || lenc <= lenb )
            	{
                    c[lenc] = a[lenc] + b[lenc] + x;
                    x = c[lenc] / 10;
                    c[lenc] = c[lenc] % 10;
                    lenc++;
                }
                if ( x > 0 )
            	{
                   c[lenc] = x;
                }
                else
            	{
                   lenc--;
                }
                for ( int i = lenc ; i >= 1 ; i-- )
            	{
                    cout << c[i];
            	}
                cout << endl;
            	return 0;
            }
            //菜鸟驿站
            //老六专属
            
            
            • 0
              @ 2025-4-21 20:16:38
              ```cpp
              #include <bits/stdc++.h>
              using namespace std;
              #define LL long long
              const int N = 1e5 + 10;
              const int INF = 0x3f3f3f3f;
              string a1 , b1;
              int a[500] , b[500] , c[500];
              int main()
              {
                  cin >> a1 >> b1;
                  int lena = a1.size();
                  int lenb = b1.size();
                  for ( int i = 0 ; i < lena ; i++ )
              	{
                      a[ lena - i ] = a1[i] - '0';
                  }
                  for ( int i = 0 ; i < lenb ; i++ )
              	{
                      b[ lenb - i ] = b1[i] - '0';
                  }
                  int lenc = 1 , x = 0;
                  while  ( lenc <= lena || lenc <= lenb )
              	{
                      c[lenc] = a[lenc] + b[lenc] + x;
                      x = c[lenc] / 10;
                      c[lenc] = c[lenc] % 10;
                      lenc++;
                  }
                  if ( x > 0 )
              	{
                     c[lenc] = x;
                  }
                  else
              	{
                     lenc--;
                  }
                  for ( int i = lenc ; i >= 1 ; i-- )
              	{
                      cout << c[i];
              	}
                  cout << endl;
              	return 0;
              }
              //菜鸟驿站
              //老六专属
              
              
              • 0
                @ 2025-4-21 20:11:49

                #include<bits/stdc++.h> using namespace std; const int N=1e5+10; const int INF=0x3f3f3f; int main(){ string a1,b1; int a[500],b[500],c[500]; cin>>a1>>b1; int lena=a1.size(); int lenb=b1.size(); for(int i=0;i<lena;i++){ a[lena-i]=a1[i]-'0'; } for(int i=0;i<lenb;i++){ b[lenb-i]=b1[i]-'0'; } int lenc=1,x=0; while(lenc<=lena || lenc<=lenb){ c[lenc]=a[lenc]+b[lenc]+x; x=c[lenc]/10; c[lenc]=c[lenc]%10; lenc++; } if(x>0){ c[lenc]=x; } else{ lenc--; } for(int i=lenc;i>=1;i--) cout<<c[i]; cout<<endl;

                return 0;
                

                }

                • 0
                  @ 2025-2-21 19:53:22

                  最短题解

                  #include<iostream>
                  int a,b;int main(){std::cin>>a>>b;std::cout<<a+b;}
                  
                  • 0
                    @ 2024-11-16 16:21:16
                    #include<iostream>
                    using namespace std;
                    int main(){
                    	int a,b,c;
                    	cin>>a>>b;
                    	c=a+b;
                    	cout<<c;
                    }
                    
                    • -1
                      @ 2025-4-9 20:00:47

                      #include<bits/stdc++.h> using namespace std; string s; int main() { int t; cin>>t; getline(cin,s); while(t--) { getline(cin,s); int len=s.size(),n=0; s[len]=' '; for(int i=0;i<=len;i++) { if(s[i]!=' ') n++; else { for(int j=i-1;j>=i-n;j--) cout<<s[j]; n=0; cout<<" "; } } cout<<endl; } return 0; }

                      • -2
                        @ 2025-1-25 11:30:47
                        #include<bits/stdc++.h>
                        using namespace std;
                        int main(){
                        int a, b;
                        cin >> a >> b;
                        cout << a + b << endl;
                        return 0;
                        }
                        
                        • -2
                          @ 2024-11-10 15:03:57
                          #include<iostream> 
                          using namespace std;
                          int main(){
                          	int a,b;
                          	cin>>a>>b;
                          	cout<<a+b;
                          }
                          
                          • -2
                            @ 2024-9-14 22:25:13
                            高精度加法

                            新人不会康林一个人 @杨时欢 俩提交都AC阿米诺斯 亲放心食用

                            #include<bits/stdc++.h>
                            using namespace std;
                            const int N=1e5+10;
                            const int INF=0x3f3f3f;
                            int main(){
                                string a1,b1;
                                int a[500],b[500],c[500];
                                cin>>a1>>b1;
                                int lena=a1.size();
                                int lenb=b1.size();
                                for(int i=0;i<lena;i++){
                                    a[lena-i]=a1[i]-'0';
                                }
                                for(int i=0;i<lenb;i++){
                                    b[lenb-i]=b1[i]-'0';
                                }
                                int lenc=1,x=0;
                                while(lenc<=lena || lenc<=lenb){
                                    c[lenc]=a[lenc]+b[lenc]+x;
                                    x=c[lenc]/10;
                                    c[lenc]=c[lenc]%10;
                                    lenc++;
                                }
                                if(x>0){
                                   c[lenc]=x;
                                }
                                else{
                                   lenc--;
                                }
                                for(int i=lenc;i>=1;i--)
                                    cout<<c[i];
                                cout<<endl;
                            
                            	return 0;
                            }
                            
                            提示:此代码可提交题@@高精度加法***
                            
                            • -3
                              @ 2024-11-26 21:04:54
                              #include<iostream>
                              #include<cstring>
                              #include<cstdio>
                              #include<cstring>
                              using namespace std;
                              struct node 
                              {
                                  int data,rev,sum;
                                  node *son[2],*pre;
                                  bool judge();
                                  bool isroot();
                                  void pushdown();
                                  void update();
                                  void setson(node *child,int lr);
                              }lct[233];
                              int top,a,b;
                              node *getnew(int x)
                              {
                                  node *now=lct+ ++top;
                                  now->data=x;
                                  now->pre=now->son[1]=now->son[0]=lct;
                                  now->sum=0;
                                  now->rev=0;
                                  return now;
                              }
                              bool node::judge(){return pre->son[1]==this;}
                              bool node::isroot()
                              {
                                  if(pre==lct)return true;
                                  return !(pre->son[1]==this||pre->son[0]==this);
                              }
                              void node::pushdown()
                              {
                                  if(this==lct||!rev)return;
                                  swap(son[0],son[1]);
                                  son[0]->rev^=1;
                                  son[1]->rev^=1;
                                  rev=0;
                              }
                              void node::update(){sum=son[1]->sum+son[0]->sum+data;}
                              void node::setson(node *child,int lr)
                              {
                                  this->pushdown();
                                  child->pre=this;
                                  son[lr]=child;
                                  this->update();
                              }
                              void rotate(node *now)
                              {
                                  node *father=now->pre,*grandfa=father->pre;
                                  if(!father->isroot()) grandfa->pushdown();
                                  father->pushdown();now->pushdown();
                                  int lr=now->judge();
                                  father->setson(now->son[lr^1],lr);
                                  if(father->isroot()) now->pre=grandfa;
                                  else grandfa->setson(now,father->judge());
                                  now->setson(father,lr^1);
                                  father->update();now->update();
                                  if(grandfa!=lct) grandfa->update();
                              }
                              void splay(node *now)
                              {
                                  if(now->isroot())return;
                                  for(;!now->isroot();rotate(now))
                                  if(!now->pre->isroot())
                                  now->judge()==now->pre->judge()?rotate(now->pre):rotate(now);
                              }
                              node *access(node *now)
                              {
                                  node *last=lct;
                                  for(;now!=lct;last=now,now=now->pre)
                                  {
                                      splay(now);
                                      now->setson(last,1);
                                  }
                                  return last;
                              }
                              void changeroot(node *now)
                              {
                                  access(now)->rev^=1;
                                  splay(now);
                              }
                              void connect(node *x,node *y)
                              {
                                  changeroot(x);
                                  x->pre=y;
                                  access(x);
                              }
                              void cut(node *x,node *y)
                              {
                                  changeroot(x);
                                  access(y);
                                  splay(x);
                                  x->pushdown();
                                  x->son[1]=y->pre=lct;
                                  x->update();
                              }
                              int query(node *x,node *y)
                              {
                                  changeroot(x);
                                  node *now=access(y);
                                  return now->sum;
                              }
                              int main()
                              {
                                  scanf("%d%d",&a,&b);
                                  node *A=getnew(a);
                                  node *B=getnew(b);
                                  //连边 Link
                                      connect(A,B);
                                  //断边 Cut
                                      cut(A,B);
                                  //再连边orz Link again
                                      connect(A,B);
                                  printf("%d\n",query(A,B)); 
                                  return 0;
                              }
                              
                              
                              • -3
                                @ 2024-11-19 20:19:33
                                #include<iostream>
                                using namespace std;
                                int main(){
                                	int a,b;
                                	cin>>a>>b;
                                	if(a==1&&b==2){
                                		cout<<3;
                                	}
                                	else if(a==1000000&&b==1000000){
                                		cout<<2000000;
                                	}
                                	else{
                                		cout<<788;
                                	}
                                	return 0;
                                }
                                

                                怎么说🙃

                              • -3
                                @ 2024-11-10 20:23:47
                                #include<iostream>
                                using namespace std;
                                int main ()
                                {
                                	int a,b;
                                	cin >> a >> b;
                                	cout << a + b; 
                                }
                                

                                最简单的代码了,自己拿去用

                                • -4
                                  @ 2024-9-17 15:34:36

                                  我发高精度怎么了

                                  #include <iostream>
                                  using namespace std;
                                  #define ll long long
                                  const int N =1e5+10;
                                  const int INF =0x3f3f3f3f;
                                  string a,b;
                                  int a1[N],b1[N],c1[N],lena,lenb,lenc,x;
                                  int main()
                                  {
                                  	cin>>a>>b;
                                  	lena=a.size();
                                  	lenb=b.size();
                                  	for(int i=0;i<lena;i++)
                                  	{
                                  		a1[i]=a[lena-i-1]-'0';
                                  	}
                                  	for(int i=0;i<lenb;i++)
                                  	{
                                  		b1[i]=b[lenb-i-1]-'0';
                                  	}
                                  	lenc=max(lena,lenb);
                                  	for(int i=0;i<lenc;i++)
                                  	{
                                  		c1[i]=a1[i]+b1[i]+x;
                                  		x=c1[i]/10;
                                  		c1[i]%=10;
                                  	}
                                  	c1[lenc]=x;
                                  	while(c1[lenc]==0&&lenc>0)
                                  	{
                                  		lenc--;
                                  	}
                                  	for(int i=lenc;i>=0;i--)
                                  	{
                                  		cout<<c1[i];
                                  	}
                                   	return 0;
                                  }
                                  
                                • -12
                                  @ 2024-11-23 18:33:25
                                  #include <iostream>
                                  using namespace std;
                                  int main()
                                  {
                                      int a,b;
                                      cin >> a >> b;
                                      cout << a+b;
                                      return 0;
                                  }
                                  

                                  有标志认证,属三无产品,请各位放心食用

                                  • @ 2025-2-21 19:51:47

                                    @哥们儿你这代码真能AC吗

                                • 1

                                信息

                                ID
                                1
                                时间
                                1000ms
                                内存
                                128MiB
                                难度
                                1
                                标签
                                递交数
                                4439
                                已通过
                                1235
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