9 条题解
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3曾致瑾 (zengzhijin) LV 6 @ 2023-1-23 15:35:33
怎么算面积——海伦公式:
S=sqrt(p(p-a)(p-b)(p-c));
p=(a+b+c)/2;
可是a,b,c都是边长,怎么算呢?
当然就用勾股定理啊!
代码:
#include <iostream> #include <cmath> using namespace std; int main(){ double x1,x2,x3,y1,y2,y3; cin>>x1>>y1>>x2>>y2>>x3>>y3; double a,b,c; a=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); b=sqrt((x2-x3)*(x2-x3)+(y2-y3)*(y2-y3)); c=sqrt((x3-x1)*(x3-x1)+(y3-y1)*(y3-y1)); double p=(a+b+c)/2; double S=sqrt(p*(p-a)*(p-b)*(p-c)); printf("%.2f",S); return 0; }
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02023-6-13 17:39:28@
#include <iostream> #include <stdio.h> #include <iomanip> #include <math.h> using namespace std; const int N = 1e6 + 10; const int INF = 0x3f3f3f3f; int main() { double a , b , c , d; float x1 , y1 , x2 , y2 , x3 , y3 , s; cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3; a = sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); b = sqrt((x1 - x3) * (x1 - x3) + (y1 - y3) * (y1 - y3)); c = sqrt((x3 - x2) * (x3 - x2) + (y3 - y2) * (y3 - y2)); d = (a + b + c) / 2; s = sqrt(d * (d - a) * (d - b) * (d - c)); cout << fixed << setprecision(2) << s; return 0; }
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-12024-10-4 13:01:25@
#include <stdio.h> #include <iostream> #include<iomanip> #include <math.h> using namespace std; int main() { float x1,y1,x2,y2,x3,y3,xy1,xy2,xy3,a,b,c,d,e,f,g,p; cin>>x1>>y1>>x2>>y2>>x3>>y3; if(x1-x20){ a = y1-y2; b = y2-y1; xy1 = max(a,b); }else{ if(y1-y20){ a = x1-x2; b = x2-x1; xy1 = max(a,b); }else{ a = y1-y2; b = y2-y1; c = max(a,b); d = x1-x2; e = x2-x1; f = max(d,e); xy1 = sqrt(cc+ff); } } if(x2-x30){ a = y2-y3; b = y3-y2; xy2 = max(a,b); }else{ if(y2-y30){ a = x2-x3; b = x3-x2; xy2 = max(a,b); }else{ a = y2-y3; b = y3-y2; c = max(a,b); d = x2-x3; e = x3-x2; f = max(d,e); xy2 = sqrt(cc+ff); } } if(x3-x10){ a = y3-y1; b = y1-y3; xy3 = max(a,b); }else{ if(y3-y10){ a = x3-x1; b = x1-x3; xy3 = max(a,b); }else{ a = y3-y1; b = y1-y3; c = max(a,b); d = x3-x1; e = x1-x3; f = max(d,e); xy3 = sqrt(cc+ff); } } p = (xy1+xy2+xy3)/2; g = sqrt(p*(p-xy1)(p-xy2)(p-xy3)); cout<<fixed<<setprecision(2)<<g; return 0; }
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-12022-10-30 16:41:02@
#include <bits/stdc++.h> using namespace std; int main(void) { double x1, y1; double x2, y2; double x3, y3; double m, n, e, p, s; cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3; m = sqrt((x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); n = sqrt((x1 - x3) * (x1 - x3) + (y1 - y3) * (y1 - y3)); e = sqrt((x3 - x2) * (x3 - x2) + (y3 - y2) * (y3 - y2)); p = (m + n + e) / 2; s = sqrt(p * (p - m) * (p - n) * (p - e)); cout << fixed << setprecision(2) << s; return 0; }
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-42022-1-2 13:59:36@
#include <stdio.h> #include <iostream> #include <math.h> using namespace std; int main() { double x1,x2,x3,y1,y2,y3; double a, b, c, p, s; cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3; a = sqrt( (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); b = sqrt( (x1 - x3) * (x1 - x3) + (y1 - y3) * (y1 - y3)); c = sqrt( (x3 - x2) * (x3 - x2) + (y3 - y2) * (y3 - y2)); p = (a + b + c) / 2; s = sqrt(p * (p - a) * (p - b) * (p -c)); printf("%.2lf",s); }
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-42022-1-2 13:58:21@
#include <stdio.h> #include <iostream> #include <math.h> #include <iomanip> using namespace std; int main() { double x1,y1,x2,y2,x3,y3; double a, b, c, p, s; cin >>x1>>y1>>x2>>y2>>x3>>y3; a=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); b=sqrt((x1-x3)*(x1-x3)+(y1-y3)*(y1-y3)); c=sqrt((x3-x2)*(x3-x2)+(y3-y2)*(y3-y2)); p=(a+b+c)/2; s=sqrt(p*(p-a)*(p-b)*(p-c)); printf ("%.2lf\n",s); }
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-42022-1-2 13:57:08@
#include <stdio.h> #include <iostream> #include <math.h> #include <iomanip> using namespace std; int main() { double x1,y1,x2,y2,x3,y3; double a, b, c, p, s; cin >>x1>>y1>>x2>>y2>>x3>>y3; a=sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2)); b=sqrt((x1-x3)*(x1-x3)+(y1-y3)*(y1-y3)); c=sqrt((x3-x2)*(x3-x2)+(y3-y2)*(y3-y2)); p=(a+b+c)/2; s=sqrt(p*(p-a)*(p-b)*(p-c)); printf ("%.2lf\n",s); }
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-62022-2-8 19:18:03@
#include <stdio.h> #include <math.h> #include <iostream> using namespace std; int main() { double x1,x2,x3,y1,y2,y3; cin >>x1>> y1 >>x2>>y2>>x3>>y3; double a,b,c; a = sqrt( (x1 - x2)(x1 - x2) + (y1-y2)(y1-y2) ); b = sqrt( (x1 - x3)(x1 - x3) + (y1-y3)(y1-y3) ); c = sqrt( (x3 - x2)(x3 - x2) + (y3-y2)(y3-y2) ); double p = (a + b + c)/2; double s = sqrt( p * (p-a) * (p-b) * (p-c)); printf("%.2lf\n",s); }
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-62022-2-8 11:43:23@
#include <stdio.h> #include <iostream> #include <math.h> using namespace std; int main() { double x1,x2,x3,y1,y2,y3; double a, b, c, p, s; cin >> x1 >> y1 >> x2 >> y2 >> x3 >> y3; a = sqrt( (x1 - x2) * (x1 - x2) + (y1 - y2) * (y1 - y2)); b = sqrt( (x1 - x3) * (x1 - x3) + (y1 - y3) * (y1 - y3)); c = sqrt( (x3 - x2) * (x3 - x2) + (y3 - y2) * (y3 - y2)); p = (a + b + c) / 2; s = sqrt(p * (p - a) * (p - b) * (p -c)); printf("%.2lf",s); }
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信息
- ID
- 825
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 3
- 标签
- 递交数
- 405
- 已通过
- 213
- 上传者