#include<iostream>
using namespace std;
int main(){
	int a,b;
	cin>>a>>b;
	cout<<a%b<<" "<<a/b;
	return 0;
}

求赞

#include <stack>
#include <iostream>
#include <iomanip>
#include <string.h>
#include <algorithm>
using namespace std;
int main() 
{
    int n,m,a,b,c;
    cin>>n>>m;
    a=n/m;
    c=a*m;
    b=n-c;
    cout<<b<<" "<<a;
}

#include <iostream> 
using namespace std;
int main()
{
	int n,m,c,d;	
	cin >>n>>m;
	c = n % m;	
	d = (n - c) / m;
	cout << c << ' ' << d << endl;
}

#include <iostream>
using namespace std;int main(){int n,m,a,b,c;cin>>n>>m;a=n/m;c=a*m;b=n-c;cout<<b<<" "<<a;}

先用数学的方式理解

#include <stack>
#include <iostream>
#include <iomanip>
#include <string.h>
#include <algorithm>
using namespace std;
int main() 
{
    int n,m,a,b,c;
    cin>>n>>m;
    a=n/m;
    c=a*m;
    b=n-c;
    cout<<b<<" "<<a;
}

#include <stdio.h>

#include

using namespace std;

int main()

{

int a,b;

cin>> a >> b ;

cout<< a % b << " " << (a - a % b) /b;

}

#include <stack>
#include <iostream>
#include <iomanip>
#include <string.h>
#include <algorithm>
using namespace std;

int main() {
int n,m,a,b,c;
cin>>n>>m;
a=n/m;
c=a*m;
b=n-c;
cout<<b<<" "<<a;
}