2 条题解
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1黄培钧 (huangpeijun) LV 7 @ 2022-8-25 12:02:19
/***************************************** Note: ******************************************/ #include <queue> #include <set> #include <math.h> #include <stack> #include <stdio.h> #include <iostream> #include <vector> #include <iomanip> #include <string.h> #include <algorithm> #include <cstdio> #include <cstring> using namespace std; const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; #define LL long long int l,r,mod; int a[N],dp[15][105][105]; int dfs(int len,int pre,bool limit) { if(len==-1) return pre==0?1:0; if(!limit&&~dp[len][pre][mod]) return dp[len][pre][mod]; int up=limit?a[len]:9; int ans=0; for(int i=0;i<=up;i++) ans+=dfs(len-1,(pre+i)%mod,limit&&i==a[len]); if(!limit) dp[len][pre][mod]=ans; return ans; } int find(int x) { memset(dp,-1,sizeof dp); int len=0; while(x) { a[len++]=x%10; x/=10; } return dfs(len-1,0,true); } int main() { while(scanf("%d%d%d",&l,&r,&mod)!=EOF) { memset(dp,-1,sizeof dp); cout<<find(r)-find(l-1)<<endl; } return 0; }
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12022-8-25 12:01:48@
#include<iostream> #include<cstdio> #include<cstring> #include<string> #include<cmath> #include<queue> #include<stack> #include<algorithm> #define int long long using namespace std; const int N=1e6+5; const int INF=0x3f3f3f3f; int n,m,a[N],dp[20][3]; int dfs(int len,int f,int flag){ if(len==-1)return 1; if(!flag&&dp[len][f==6]!=0)return dp[len][f==6]; int nid=flag?a[len]:9; int ans=0; for(int i=0;i<=nid;i++){ if((i==4)||(i==2&&f==6))continue; ans+=dfs(len-1,i,flag&&i==a[len]); } if(!flag){ dp[len][f==6]=ans; } return ans; } int find(int num){ int len=0; while(num!=0){ a[len]=num%10; len++; num/=10; } return dfs(len-1,-1,true); } signed main(){ while(scanf("%lld%lld",&n,&m)){ if(n==0&&m==0)return 0; cout << find(m)-find(n-1) << endl; } return 0; }
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信息
- ID
- 482
- 时间
- 1000ms
- 内存
- 512MiB
- 难度
- 7
- 标签
- 递交数
- 90
- 已通过
- 24
- 上传者