5 条题解

  • 1
    @ 2026-3-22 15:41:46

    虽然只有一种味,但真的很 鲜~

    向日葵味

    #include<bits/stdc++.h>
    using namespace std;
    int n, m;  
    int a[10000005];  
    int main(){
        cin >> n >> m;  
        for(int i=1; i<=n; i++){
            cin >> a[i];
        }
    
        for(int i=1; i<=m; i++){  
            int ans;  
            cin >> ans;
            int l = 1, r = n, res = -1;  
            while (l <= r) {
                int mid = (l + r) / 2;
                if (a[mid] == ans) {
                    res = mid;  
                    r = mid - 1;  
                } else if (a[mid] < ans) {
                    l = mid + 1;
                } else {
                    r = mid - 1;
                }
            }
            cout << res << "\n";  
        }
        return 0;
    }
    
    • 0
      @ 2025-9-20 14:17:21
      #include<bits/stdc++.h>
      using namespace std;
      long long a[10000000],b[1000000],n,x,nnn;
      int main(){
          cin >> n >> x;
          for(int i=0; i<n; i++){
              cin >> a[i];
          }
          for(int i=0; i<x; i++){
              int l=0,r=n-1,mid=0,ans;
              bool f=0;
              cin >> ans;
              while(l<=r){
                  mid=(l+r)/2;
                  
                  if(a[mid]==ans){
                      
                      f=1;
                      r=mid-1;
                      nnn=mid;
                  }
                  if(a[mid]<ans) l=mid+1;
                  else r=mid-1;
              }
      
              if(f==0) cout << -1 << "\n";
              else cout << nnn+1 << "\n";
          }
          return 0;
      }
      
      • 0
        @ 2025-4-26 21:22:01

        1000分,拿走

        #include<bits/stdc++.h>
        using namespace std;
        const int N=1e5+10;
        const int INF=0x3f3f3f3f;
        #define LL long long
        #define ull unsigned long long
        int n,m,a[N],ub[114514];
        'int main(){
        	int anser[594088],sum;
        	cin>>n>>m;
        	for(int i=1;i<=n;i++){
        		cin>>a[i];
        	}
        	for(int i=1;i<=m;i++){
        		cin>>ub[i];
        		int l=1,r=n;
        		sum=0;	
        	while(l<=r){
        		int mid=(l+r)/2;
        		if(a[mid]==ub[i])'{
        			sum=mid;
        			r=mid-1;
        		}
        		else if(a[mid]>ub[i]){
        			r=mid-1;
        		}
        		else{
        			l=mid+1;
        		}
        	}
        		if(sum){
        			anser[i]=sum;
        		}
        		else{
        			anser[i]=-1;
        		}
        	}
        	for(int i=1;i<=m;i++){
        		cout<<anser[i]<<endl;
        	}	
        	return 1;
        }                            '   
        
        #include<bits/stdc++.h>
        using namespace std;
        const int N=1e5+10;
        const int INF=0x3f3f3f3f;
        #define LL long long
        #define ull unsigned long long
        int n,m,a[N],ub[114514];
        int main(){
        	int ans[594088],sum;
        	cin>>n>>m;
        	for(int i=1;i<=n;i++){
        		cin>>a[i];
        	}
        	for(int i=1;i<=m;i++){
        		cin>>ub[i];
        		int l=1,r=n;
        		sum=0;	
        	while(l<=r){
        		int mid=(l+r)/2;
        		if(a[mid]==ub[i]){
        			sum=mid;
        			r=mid-1;
        		}
        		else if(a[mid]>ub[i]){
        			r=mid-1;
        		}
        		else{
        			l=mid+1;
        		}
        	}
        		if(sum){
        			ans[i]=sum;
        		}
        		else{
        			ans[i]=-1;
        		}
        	}
        	for(int i=1;i<=m;i++){
        		cout<<ans[i]<<endl;
        	}	
        	return 0;
        }
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        阿妈特拉斯

        • @ 2025-4-26 21:33:15

          不长不短会变成都不会补充蛋白和传播 嘻嘻嘻

      • -3
        @ 2025-4-22 19:16:13

        不长不短会变成都不会补充蛋白和传播

        • -4
          @ 2024-12-17 16:24:38
          #include<bits/stdc++.h>
          using namespace std;
          int main(){
          	int n,m,a[100001],b[100001],c[100005];
          	cin>>n>>m;
          	for(int i=1;i<=n;i++){
          		cin>>a[i];
          	}
          	for(int i=1;i<=m;i++){
          		cin>>b[i];
          		int l=1,r=n,ans=0;	
          	while(l<=r){
          		int mid=(l+r)/2;
          		if(a[mid]==b[i]){
          			ans=mid;
          			r=mid-1;
          		}
          		else if(a[mid]>b[i]){
          			r=mid-1;
          		}
          		else{
          			l=mid+1;
          		}
          	}
          		if(ans==0){
          			c[i]=-1;
          		}
          		else{
          			c[i]=ans;
          		}
          	}
          	for(int i=1;i<=m;i++){
          		cout<<c[i]<<endl;
          	}
          	
          
          	
          	
          	return 0;
          }
          小鸟
          
          • 1

          信息

          ID
          3098
          时间
          1000ms
          内存
          256MiB
          难度
          2
          标签
          递交数
          116
          已通过
          27
          上传者