1 条题解
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0赵青海 (huhe) LV 7 SU @ 2022-9-9 21:11:48
/***************************************** Note: ******************************************/ #include <queue> #include <math.h> #include <stack> #include <stdio.h> #include <iostream> #include <vector> #include <iomanip> #include <string.h> #include <algorithm> using namespace std; #define int long long const int N = 1e7 + 10; const int mod = 1e7 + 7; int n , a[N] , sum =0 , k; struct node { int s[4][4]; node () { memset(s,0 , sizeof s); } }num , ans; node operator * (const node a , const node b) { node z; for(int i = 0 ; i < 3 ; i++) for(int j = 0 ; j < 3 ; j++) for(int k = 0 ; k < 3 ; k++) z.s[i][j] = (z.s[i][j] + a.s[i][k] * b.s[k][j]) % mod; return z; } void calc(int p) { ans.s[0][0] = ans.s[1][1] = ans.s[2][2] = 1; while(p) { if(p&1) ans = ans * num; p >>= 1; num = num * num; } } signed main() { cin >> n >> k; for(int i = 0; i < n ; i++) { scanf("%lld", &a[i]); sum = (sum + a[i])%mod; } sort(a,a+n); int a1 = a[n-1] , a2 = a[n-2]; if(a2 < 0) { int l = ceil(fabs(a2)/a1); sum = (sum + (a2 + a1 + a2 + a1 * l)*(l)/2 )%mod; a2 = a2 + a1*l; k-= l; } a1 %= mod , a2 %= mod; num.s[1][1] = num.s[0][0] = num.s[1][2] = num.s[1][0] = num.s[2][1] = num.s[2][0] = 1; calc(k); sum = (ans.s[0][0] * sum + ans.s[1][0] * a1 + ans.s[2][0] * a2) % mod; cout << sum << endl; return 0; }
- 1
信息
- ID
- 2019
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 8
- 标签
- 递交数
- 74
- 已通过
- 10
- 上传者