3 条题解

  • 2
    @ 2023-4-9 19:49:22
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #define  N  510000
    using  namespace  std;
    typedef  long  long  LL;
    int  bst[N],n;
    inline  int  lowbit(int  x){return  x&-x;}
    void  ins(int  x)
    {
    	while(x<=n)
    	{
    		bst[x]++;
    		x+=lowbit(x);
    	}
    }
    int  findans(int  x)
    {
    	int  ans=0;
    	while(x>=1)
    	{
    		ans+=bst[x];
    		x-=lowbit(x);
    	}
    	return  ans;
    }
    int  a[N],b[N],c[N];
    inline  bool  cmp(int  x,int  y){return  a[x]<a[y];}
    int  main()
    {
    	a[0]=-9999;
    	while(1)
    	{
    		memset(bst,0,sizeof(bst));
    		scanf("%d",&n);
    		if(n==0)break;
    		for(int  i=1;i<=n;i++){scanf("%d",&a[i]);b[i]=i;}
    		sort(b+1,b+n+1,cmp);
    		int  cnt=0;
    		for(int  i=1;i<=n;i++)
    		{
    			if(a[b[i]]!=a[b[i-1]])cnt++;
    			c[b[i]]=cnt;
    		}
    		LL  ans=0;
    		for(int  i=1;i<=n;i++)
    		{
    			ans+=i-1-findans(c[i]);ins(c[i]);
    		}
    		printf("%lld\n",ans);
    	}
    	return  0;
    }
    
    
    • 0
      @ 2024-5-28 16:42:55
      #include<cstdio>
      #include<cstring>
      #include<algorithm>
      #define  N  510000
      using  namespace  std;
      typedef  long  long  LL;
      int  bst[N],n;
      inline  int  lowbit(int  x){return  x&-x;}
      void  ins(int  x)
      {
      	while(x<=n)
      	{
      		bst[x]++;
      		x+=lowbit(x);
      	}
      }
      int  findans(int  x)
      {
      	int  ans=0;
      	while(x>=1)
      	{
      		ans+=bst[x];
      		x-=lowbit(x);
      	}
      	return  ans;
      }
      int  a[N],b[N],c[N];
      inline  bool  cmp(int  x,int  y){return  a[x]<a[y];}
      int  main()
      {
      	a[0]=-9999;
      	while(1)
      	{
      		memset(bst,0,sizeof(bst));
      		scanf("%d",&n);
      		if(n==0)break;
      		for(int  i=1;i<=n;i++){scanf("%d",&a[i]);b[i]=i;}
      		sort(b+1,b+n+1,cmp);
      		int  cnt=0;
      		for(int  i=1;i<=n;i++)
      		{
      			if(a[b[i]]!=a[b[i-1]])cnt++;
      			c[b[i]]=cnt;
      		}
      		LL  ans=0;
      		for(int  i=1;i<=n;i++)
      		{
      			ans+=i-1-findans(c[i]);ins(c[i]);
      		}
      		printf("%lld\n",ans);
      	}
      	return  0;
      }
      
      //钟鼎皓
      
      • 0
        #include <cstdio>
        #include <iostream>
        #include <string.h>
        using namespace std;
        
        const int N=5e5+10;
        long long a[N],b[N];
        int n;
        long long ans;
        
        void Mergesort(int st,int ed)
        {
        	if(st==ed)return;
        	int mid=(st+ed)/2,i=st,j=mid+1,k=st;
        	
        	Mergesort(st,mid);
        	Mergesort(mid+1,ed);
        	
        	while(i<=mid && j<=ed)
        	{
        		if(a[i]<=a[j])
        		{
        			b[k++]=a[i++];
        		}
            	else
            	{
            		b[k++]=a[j++];
        			ans+=mid-i+1;
        		}	
        	}
        	while(i<=mid)b[k++]=a[i++];
            while(j<=ed)b[k++]=a[j++];
            for(int l=st;l<=ed;l++)
            	a[l]=b[l];
        }
        int main()
        {
            while(scanf("%d",&n) && n!=0)
            {
                ans=0;
        		memset(b,0,sizeof(b));
                for(int i=1;i<=n;++i)
                {
                    scanf("%lld",&a[i]);
                }
                Mergesort(1,n);
                printf("%lld\n",ans);
            }
        	return 0;
        }
        

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        • 1

        信息

        ID
        19
        时间
        1000ms
        内存
        128MiB
        难度
        1
        标签
        递交数
        135
        已通过
        92
        上传者