5 条题解
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5庄力 (zhuangli2018) LV 10 @ 2023-8-6 11:28:50
#include<bits/stdc++.h> #define INF 0x3f3f3f3f using namespace std; int f[10005],v[110],w[110],num[110]; int n,m; void OneZeroPack(int m,int v,int w) { for(int i=m;i>=v;i--)f[i]=max(f[i],f[i-v]+w); } void CompletePack(int m,int v,int w) { for(int i=v;i<=m;i++)f[i]=max(f[i],f[i-v]+w); } void MultiplePack(int m,int v,int w,int num){ if(v*num>=m){CompletePack(m,v,w);return ;} int k=1; for(k=1;k<=num;k<<=1){OneZeroPack(m,k*v,k*w);num=num-k;} if(num)OneZeroPack(m,num*v,num*w); } int main(){ while(cin>>m>>n){ for(int i=0;i<n;i++)cin>>v[i]>>w[i]>>num[i]; memset(f,0,sizeof(f)); for(int i=0;i<n;i++)MultiplePack(m,v[i],w[i],num[i]); cout<<f[m]<<endl; } return 0; }
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12023-11-11 10:18:05@
#include<bits/stdc++.h> #define INF 0x3f3f3f3f using namespace std; int f[10005],v[110],w[110],num[110]; int n,m; void OneZeroPack(int m,int v,int w) { for(int i=m;i>=v;i--)f[i]=max(f[i],f[i-v]+w); } void CompletePack(int m,int v,int w) { for(int i=v;i<=m;i++)f[i]=max(f[i],f[i-v]+w); } void MultiplePack(int m,int v,int w,int num){ if(vnum>=m){CompletePack(m,v,w);return ;} int k=1; for(k=1;k<=num;k<<=1){OneZeroPack(m,kv,kw);num=num-k;} if(num)OneZeroPack(m,numv,num*w); } int main(){ while(cin>>m>>n){ for(int i=0;i<n;i++)cin>>v[i]>>w[i]>>num[i]; memset(f,0,sizeof(f)); for(int i=0;i<n;i++)MultiplePack(m,v[i],w[i],num[i]); cout<<f[m]<<endl; } return 0; }
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12023-8-6 11:30:03@
#include <iostream> #include <cmath> #include <cstring> #include <string.h> #include <queue> #include <stack> #include <map> using namespace std; const int N = 1e5 + 10; const int INF = 0x3f3f3f3f; int w[N],v[N],dp[N],n,m,len ,ww,vv,num; int main(){ cin >> m >> n; for(int i=1; i<=n ;i++) { cin >> ww >> vv >> num; int cnt = 1; while(cnt <= num){ w[++len]=cnt*ww; v[len]=cnt*vv; num -= cnt; cnt <<= 1; } if(num > 0){ w[++len]=num*ww; v[len]=num*vv; } } n = len; for(int i=1; i<=n; i++) { for(int j=m; j>=w[i]; j--){ dp[j]=max(dp[j],dp[j-w[i]]+v[i]); } } cout << dp[m]; return 0; }//二进制解法
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-22023-8-6 11:29:20@
#include<iostream>
#include<queue>
#include<map>
#include<cstring>
#include<string.h>
#include<algorithm>
#include<cstdio>
using namespace std;
const int N=6e3+10;
const int INF=0x3f3f3f3f;
int m,n,w[N],v[N],dp[N],i,j,ww,vv,len,num1,cnt=1;
int main(){
cin>>m>>n; for(i=1;i<=n;i++){ cin>>ww>>vv>>num1; cnt=1; while(cnt<=num1){ w[++len]=cnt*ww; v[len]=cnt*vv; num1-=cnt; cnt<<=1; } if(num1>0){ w[++len]=num1*ww; v[len]=num1*vv; } } n=len; for(i=1;i<=n;i++){ for(j=m;j>=w[i];j--){ dp[j]=max(dp[j],dp[j-w[i]]+v[i]); } } cout<<dp[m]<<endl; return 0;
}
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-22023-4-21 21:19:22@
#include <iostream> #include <cstdio> #include <algorithm> #include <string> #include <cstring> #include <cstdlib> #include <cmath> #include <stack> #include <queue> #include <set> #include <map> #include <vector> #include <ctime> #include <cctype> #include <bitset> #include <utility> #include <sstream> #include <complex> #include <iomanip> #define inf 0x3f3f3f3f typedef long long ll; using namespace std; int N,V,dp[210]; struct node { int n;//空间 int c;//价值 int w;//数量 } p[210]; int main() { scanf("%d%d",&V,&N); for(int i=1; i<=N; i++) scanf("%d%d%d",&p[i].n,&p[i].c,&p[i].w); for(int i=1; i<=N; i++) { if(p[i].w*p[i].n>=V) { for(int j=p[i].n; j<=V; j++) dp[j]=max(dp[j],dp[j-p[i].n]+p[i].c); } for(int k=1; k<p[i].w; p[i].w-=k,k=k*2) for(int j=V; j>=k*p[i].n; j--) dp[j]=max(dp[j],dp[j-k*p[i].n]+p[i].c*k); for(int j=V; j>=p[i].n*p[i].w; j--) dp[j]=max(dp[j],dp[j-p[i].w*p[i].n]+p[i].c*p[i].w); } printf("%d\n",dp[V]); return 0; }
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信息
- ID
- 1734
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 5
- 标签
- 递交数
- 65
- 已通过
- 27
- 上传者