8 条题解

  • 1
    #include <iostream>
    #include <bits/stdc++.h>
    using namespace std;
    const int N=1e2+10;
    const int INF=0x3f3f3f3f;
    int main()
    {
    	char a[N],b[N]; 
    	while(cin>>a>>b)
    	{
    		cout<<a<<b ;
    	}
    }
    

    唯一对题解

    其他A不了(加了endl)

    • 1
      @ 2023-5-23 22:18:37

      #include<bits/stdc++.h> using namespace std; const int N=1e2+10; char a[N],b[N];

      int main(){ while(cin>>a>>b){ cout <<strcat(a,b)<<endl; }

      return 0;
      

      }

      • 1
        @ 2023-4-19 19:30:55

        对不起,我有反骨。a.append(b);和a+=b这种行为都是拼接字符串

        反骨法:

        #include<iostream>
        #include<string.h>
        using namespace std;
        string a,b;
        int main(){
        	while(cin>>a>>b){
        		a.append(b);
        		cout<<a<<"\n";
        	}
        	return 0;
        }
        

        正常做法:

        #include<iostream>
        using namespace std;
        string a,b;
        int main(){
        	while(cin>>a>>b)cout<<a<<b<<"\n";
        	return 0;
        }
        
        • 1
          @ 2022-2-19 11:05:34
          #include <stdio.h>
          #include <iostream>
          #include <string.h>
          const int N = 2e5 + 10;
          using namespace std;
          int main()
          {
              string a,b;
              while(cin >> a >> b)
              	cout << a << b <<endl;
              return 0;
          }
          
          
          • 1
            @ 2022-2-19 11:04:15
            #include <stdio.h>
            #include <iostream>
            #include <string.h>
            const int N = 2e5 + 10;
            using namespace std;
            int main()
            {
                string a,b;
                while(cin >> a >> b)
                    cout << a << b << endl;
            }
            
            • 0
              @ 2023-5-19 19:17:10
              #include <iostream>
              #include <bits/stdc++.h>
              using namespace std;
              const int N=1e2+10;
              const int INF=0x3f3f3f3f;
              int main()
              {
              	char a[N],b[N]; 
              	while(cin>>a>>b)
              	{
              		cout<<a<<b<<endl;
              	}
              }
              
              
              • 0
                @ 2023-5-17 22:00:22
                #include <stdio.h>
                #include <string.h>
                #include <queue>
                #include <math.h>
                #include <vector>
                #include <algorithm>
                #include <iomanip>
                #include <stack>
                #include <cstring>
                #include <bits/stdc++.h>
                #include <algorithm>
                using namespace std;
                char a[110],b[110];
                
                int main(){
                	while(cin >> a >> b){
                		cout << strcat(a,b) << endl;
                	}
                	return 0;
                
                }
                
                • 0
                  @ 2022-2-19 11:06:06
                  #include <stdio.h>
                  #include <iostream>
                  #include <string.h>
                  using namespace std;
                  int main()
                  {
                  	string a,b;
                  	while(cin>>a>>b)
                  		cout<<a<<b<<endl;
                  }
                  
                  • 1

                  信息

                  ID
                  1163
                  时间
                  1000ms
                  内存
                  32MiB
                  难度
                  7
                  标签
                  递交数
                  568
                  已通过
                  150
                  上传者