#include <stdio.h> #include using namespace std; const int N = 10+ 10; const int INF = 0x3f3f3f3f; int n, a[N][N],x,y,num; int main(){ cin >>n; x=1,y=1;//起点位置 while(num<n*n) { //向下填数 while(x<=n) a[x++][y]=++num; //回正轨 x=1,y++; } for(int i=1;i<=n;i++) { for(int j=1;j<=n;j++) { cout <<a[i][j]<<" "; } cout<<endl; }

return 0;

}