其实这题很简单，只需要埃氏筛法就行，不知为啥各位大老搞这么复杂？ #include <bits/stdc++.h> using namespace std;

bool flag[10005]; void isPrime() { memset(flag, true, sizeof(flag)); flag[0] = flag[1] = false; for (int i = 2; i <= 10000; i++) { if (flag[i]) { for (int j = 2; j <= 10000 / i; j++) { flag[i * j] = false; } } } }

int main() { isPrime(); int x, y; cin >> x >> y; bool vis = false; for (int i = x; i <= y; i++) { if (flag[i] && flag[i+2]) { cout << i << " " << i + 2 << endl; vis = true; } } if (!vis) cout << "empty" << endl; return 0; }