包对的

#include <bits/stdc++.h>

using namespace std;

const int N = 1e5 + 10;-

int main() { int n[10005], ans = 0, i = 1, cnt = 0; char a; while(cin >> n[i] >> a) { ans += n[i++]; cnt++; } for(int i = 1; i <= cnt; i++) { cout << n[i]; if(i != cnt) { cout << "+"; } else { cout << "="; } } cout << ans << endl; return 0; }