3 条题解
-
0
#include <iostream> #include <cmath> using namespace std; typedef long long ll; int main() { int k; cin >> k; while (k--) { ll n, e, d; cin >> n >> e >> d; ll m = n - e * d + 2; ll delta = m * m - 4 * n; if (delta < 0) { cout << "NO\n"; continue; } ll root = sqrt(delta); if (root * root != delta) { cout << "NO\n"; continue; } ll p = (m - root) / 2; ll q = (m + root) / 2; if (p > 0 && q > 0 && p * q == n) { cout << p << " " << q << "\n"; } else { cout << "NO\n"; } } return 0; }
信息
- ID
- 2917
- 时间
- 1000ms
- 内存
- 256MiB
- 难度
- 8
- 标签
- 递交数
- 193
- 已通过
- 48
- 上传者