1 条题解

  • 1
    @ 2026-9-2 20:40:21
    #include <vector>
    using namespace std;
    
    int main() {
        int n, m;
        double d, a1, an;
        cin >> n >> d >> m >> a1 >> an;
        vector<double> c(n + 1), s(n + 1);
        c[1] = a1; s[1] = 0;
        c[2] = 0;  s[2] = 1;
        for (int i = 2; i < n; i++) {
            c[i + 1] = c[i - 1] - 2 * c[i] + 2 * d;
            s[i + 1] = s[i - 1] - 2 * s[i];
        }
        double a2 = (an - c[n]) / s[n];
        double am = c[m] + s[m] * a2;
        cout << (long long)am << endl;
        return 0;
    }
    
    
    

    信息

    ID
    1782
    时间
    1000ms
    内存
    256MiB
    难度
    10
    标签
    递交数
    1
    已通过
    1
    上传者