2 条题解
-
1
#include <bits/stdc++.h> using namespace std; #define LL long long const int N = 1e2 + 10; const int INF = 0x3f3f3f3f; int n , a[N][N]; void f( int x ) { if ( x == n ) { return; } for ( int i = 1 ; i <= x ; i++ ) { a[ ( n - x ) / 2 ][ ( n - x ) / 2 + i ] = 1; } for ( int i = 1 ; i <= x ; i++ ) { a[ ( n - x ) / 2 + i ][ ( n - x ) / 2 ] = 2; } for ( int i = 1 ; i <= x ; i++ ) { a[ n + 1 - ( n - x ) / 2 ][ ( n - x ) / 2 + i ] = 3; } for ( int i = 1 ; i <= x ; i++ ) { a[ ( n - x ) / 2 + i ][ n + 1 - ( n - x ) / 2 ] = 4; } f( x + 2 ); } int main() { cin >> n; if ( n % 2 == 1 ) { f(1); } else { f(2); } for ( int i = 1 ; i <= n ; i++ ) { for ( int j = 1 ; j <= n ; j++ ) { cout << a[i][j] << " "; } cout << endl; } return 0; } //菜鸟驿站 //老六专属
信息
- ID
- 1037
- 时间
- 1000ms
- 内存
- 128MiB
- 难度
- 8
- 标签
- 递交数
- 15
- 已通过
- 7
- 上传者